Discussion:
Three rational triples
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HenHanna
2024-09-13 02:19:31 UTC
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I discovered that these three sets of three positive rationals have an
9/2, 4/3, 7/6
49/15, 25/21, 54/35
49/2, 4/7, 27/14
If nobody figures it out, I will provide the answer in a week.
that sounds good.
guido wugi
2024-09-13 20:30:47 UTC
Permalink
I discovered that these three sets of three positive rationals have an
9/2, 4/3, 7/6
49/15, 25/21, 54/35
49/2, 4/7, 27/14
If nobody figures it out, I will provide the answer in a week.
        that sounds good.
They are three, they are positive, they are rationals, they're written
in the same form and the same number base or whatsitcalled, they are
mentioned here (and no others are).
Anything else yet?
--
guido wugi :o)
HenHanna
2024-09-19 17:11:53 UTC
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Each of them has a sum that's equal to its product and is an integer.
i think one person said exactly that.
----------- Who and when? I didn't see any such post.


So this post below didn't get to your site (or Newsreader).
I discovered that these three sets of three positive rationals have an
9/2, 4/3, 7/6
49/15, 25/21, 54/35
49/2, 4/7, 27/14
If nobody figures it out, I will provide the answer in a week.
that sounds good.
SPOILER
The sum of each triplet is the same as its product.
9/2*4/3*7/6 = 9/2+4/3+7/6 = 7
49/15*25/21*54/35 = 49/15+25/21+54/35 = 6
49/2*4/7*27/14 = 49/2+4/7+27/14 = 27
Please reply to ilanlmayer at gmail dot com
__/\__
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__/\\ //\__ Ilan Mayer
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/__ __\ Toronto, Canada
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Keith F. Lynch
2024-09-20 00:07:29 UTC
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Post by HenHanna
So this post below didn't get to your site (or Newsreader).
. . .
The sum of each triplet is the same as its product.
9/2*4/3*7/6 = 9/2+4/3+7/6 = 7
49/15*25/21*54/35 = 49/15+25/21+54/35 = 6
49/2*4/7*27/14 = 49/2+4/7+27/14 = 27
Please reply to ilanlmayer at gmail dot com
__/\__
\ /
__/\\ //\__ Ilan Mayer
\ /
/__ __\ Toronto, Canada
/__ __\
||
Thanks for forwarding that. I don't know why that post never showed
up on Panix.
--
Keith F. Lynch - http://keithlynch.net/
Please see http://keithlynch.net/email.html before emailing me.
IlanMayer
2024-09-13 12:58:08 UTC
Permalink
Post by HenHanna
I discovered that these three sets of three positive rationals have an
9/2, 4/3, 7/6
49/15, 25/21, 54/35
49/2, 4/7, 27/14
If nobody figures it out, I will provide the answer in a week.
that sounds good.
SPOILER
The sum of each triplet is the same as its product.

9/2*4/3*7/6 = 9/2+4/3+7/6 = 7
49/15*25/21*54/35 = 49/15+25/21+54/35 = 6
49/2*4/7*27/14 = 49/2+4/7+27/14 = 27

Please reply to ilanlmayer at gmail dot com

__/\__
\ /
__/\\ //\__ Ilan Mayer
\ /
/__ __\ Toronto, Canada
/__ __\
||
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